<?xml version="1.0" encoding="UTF-8" standalone="yes" ?>
<!DOCTYPE bugzilla SYSTEM "http://www.seatribe.se/bt/bugzilla.dtd">

<bugzilla version="4.2"
          urlbase="http://www.seatribe.se/bt/"
          
          maintainer="fredrik@dolda2000.com"
>

    <bug>
          <bug_id>69</bug_id>
          
          <creation_ts>2012-10-06 09:26:00 +0200</creation_ts>
          <short_desc>Smelting yields are bugged?</short_desc>
          <delta_ts>2012-11-28 23:57:16 +0100</delta_ts>
          <reporter_accessible>1</reporter_accessible>
          <cclist_accessible>1</cclist_accessible>
          <classification_id>1</classification_id>
          <classification>Unclassified</classification>
          <product>Salem</product>
          <component>Game</component>
          <version>unspecified</version>
          <rep_platform>PC</rep_platform>
          <op_sys>Windows</op_sys>
          <bug_status>IN_PROGRESS</bug_status>
          <resolution></resolution>
          
          
          <bug_file_loc></bug_file_loc>
          <status_whiteboard></status_whiteboard>
          <keywords></keywords>
          <priority>---</priority>
          <bug_severity>normal</bug_severity>
          <target_milestone>---</target_milestone>
          
          
          <everconfirmed>1</everconfirmed>
          <reporter>verballyokay</reporter>
          <assigned_to name="loftar">fredrik</assigned_to>
          

      

      

      

          <long_desc isprivate="0">
            <commentid>226</commentid>
            <who name="">verballyokay</who>
            <bug_when>2012-10-06 09:26:31 +0200</bug_when>
            <thetext>From what I&apos;ve been told the theoretical average yield should follow following formula:

average yield = (#&quot;iron ores&quot;) * ( 0.01 * #&quot;limes&quot; + 0.01) and supposidly that formula was given from a developer himself at one point. 

According to that formula, using 8 limes &amp; 17 ores should on average yield 1.53 iron bars per batch. However, a source has tested doing over 100 batches on a newly built smelter(noone else used that smelter) and reached the conclusion that the average yield was roughly 1.83, which is a lot higher than the theoretical 1.53. 

If the given formula is supposed to still be accurate, then the results from that source indicate that there is a bug which increases his average yield significantely for 8 limes &amp; 17 ores.</thetext>
          </long_desc>
          <long_desc isprivate="0">
            <commentid>334</commentid>
            <who name="loftar">fredrik</who>
            <bug_when>2012-11-28 23:57:16 +0100</bug_when>
            <thetext>That formula is wrong, though; it should be (0.01 * #limes + 0.02), so 0.1 in your case, which should give an average yield of 1.7 bars per smelter. 1.83 is obviously still higher, though. I&apos;m not sure if it&apos;s within a margin where it can be ascribed to accounting error or not.</thetext>
          </long_desc>
      
      

    </bug>

</bugzilla>